document.write( "Question 969628: The length of a rectangle is 7 inches longer than it is wide. If the area is 120 square inches, what are the dimensions of the rectangle?
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Algebra.Com's Answer #592455 by Boreal(15235)\"\" \"About 
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Length * width =Area\r
\n" ); document.write( "\n" ); document.write( "Length =x
\n" ); document.write( "Width = x-7, because the length is longer than wide, and we subtract.\r
\n" ); document.write( "\n" ); document.write( "area= x(x-7) and units are in^2 because base units are inches.\r
\n" ); document.write( "\n" ); document.write( "x^2-7x=120\r
\n" ); document.write( "\n" ); document.write( "subtract 120 from each side\r
\n" ); document.write( "\n" ); document.write( "x^2-7x-120=0\r
\n" ); document.write( "\n" ); document.write( "Factor using 15 and 8. The 15 must be negative so that the middle term is negative.\r
\n" ); document.write( "\n" ); document.write( "(x-15) (x+8)=0\r
\n" ); document.write( "\n" ); document.write( "set each =0, because one factor must equal zero for the whole thing to equal zero.\r
\n" ); document.write( "\n" ); document.write( "x-15=0; x=15 inches\r
\n" ); document.write( "\n" ); document.write( "x+8=0; x= -8 inches. This is impossible, so this root is not used.\r
\n" ); document.write( "\n" ); document.write( "The length is 15 inches.\r
\n" ); document.write( "\n" ); document.write( "The width is 15-7 or 8 inches.\r
\n" ); document.write( "\n" ); document.write( "The area is 15 in * 8 in=120 in^2, which matches the required area.\r
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