document.write( "Question 969536: Premises:
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document.write( "1.) V->H
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document.write( "2.) ~V->S
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document.write( "3.) ~H -> ~S
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document.write( "Conclusion:
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document.write( "/H \n" );
document.write( "
Algebra.Com's Answer #592429 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! Premises: \n" ); document.write( "1.) V->H \n" ); document.write( "2.) ~V->S \n" ); document.write( "3.) ~H -> ~S \n" ); document.write( "Conclusion: \n" ); document.write( "/H \n" ); document.write( " \r\n" ); document.write( "4. ~~S->~~H contrapositive, 3 \r\n" ); document.write( "5. S->H double negation, 4\r\n" ); document.write( "6. ~V->H hypothetical syllogism 2,5 \r\n" ); document.write( "7. ~H->~~V contrapositive, 6 \r\n" ); document.write( "8. ~H->V double negation, 7\r\n" ); document.write( "9. ~H->~V contrapositive, 1\r\n" ); document.write( "10. V or ~V tautology\r\n" ); document.write( "11. H or H constructive dilemma, 1,6,10\r\n" ); document.write( "\r\n" ); document.write( " Here's an explanation of step 11:\r\n" ); document.write( " constructive dilemma says: p->q,r->s,(p or r), / (q or s)\r\n" ); document.write( " we substitute p=V, q=H, r=~V, s=H \r\n" ); document.write( " V->H,~V->H,(V or ~V), / (H or H)\r\n" ); document.write( " 1, 6, 10, / 11\r\n" ); document.write( "12. H simplification (or idempotent), 11\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |