document.write( "Question 969598: Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed? \n" ); document.write( "
Algebra.Com's Answer #592422 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 5 liters ANSWER\r \n" ); document.write( "\n" ); document.write( "Let x=liters of 10% solution.\r \n" ); document.write( "\n" ); document.write( "10 liters * 0.04 (4%)acid= 0.4 acid-liters (it's a strange unit, but stay with me)\r \n" ); document.write( "\n" ); document.write( "x liters * 0.10 (10%) acid= 0.1x acid-liters\r \n" ); document.write( "\n" ); document.write( "I want a 6% solution (.06 acid) amount is 10+x liters (10 from 4%, x from 10%)\r \n" ); document.write( "\n" ); document.write( "(10+x) liters *.06%=0.06(10-x) acid-liters\r \n" ); document.write( "\n" ); document.write( "Let's distribute that to get 0.6-0.06 x\r \n" ); document.write( "\n" ); document.write( "Now add the first two solutions and let them equal the third\r \n" ); document.write( "\n" ); document.write( "0.4 a-l +0.1x a-l=0.6 a-l-0.06x a-l\r \n" ); document.write( "\n" ); document.write( "subtract 0.4 a-l from each side\r \n" ); document.write( "\n" ); document.write( "0.1 x a-l=0.2 a-l +0.06x a-l \n" ); document.write( "Subtract 0.06 a-l from each side\r \n" ); document.write( "\n" ); document.write( "0.04x a-l=0.2 a-l \n" ); document.write( "divide by 0.04 the units are acid only, so we will be left with liters as the units, which is what we want.\r \n" ); document.write( "\n" ); document.write( "x=5 liters.\r \n" ); document.write( "\n" ); document.write( "Let's see if this works \n" ); document.write( "10 *(0.04) + 5 (.10)=.4 +.5=0.9 I am multiplying liters times per cent acid for the two. \n" ); document.write( "15*(0.06)=0.9 This is the final solution.\r \n" ); document.write( "\n" ); document.write( "That checks\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |