document.write( "Question 969596: Sketch a graph of a function that has a horizontal asymptote of y=5, a vertical asymptote of x=2, an x intercept of -1, and a hole when x=1 and give one possible equation for it. \n" ); document.write( "
Algebra.Com's Answer #592420 by josgarithmetic(39618)\"\" \"About 
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Horizontal Asymptote: Degree of numerator equals degree of denominator.\r
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\n" ); document.write( "\n" ); document.write( "Vertical Asymptote x=2: \"something%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "x-intercept -1: \"%28something%28x%2B1%29%29%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Hole and undefined at x=1: \"%28%28x%2B1%29%28x-1%29%29%2F%28%28x-2%29%28x-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Almost finished. You want horizontal asymptote y=5. Leading terms must become increasingly large and positive as x goes to the right or left unbounded and ratio must approach 5.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%285%28x%2B1%29%28x-1%29%29%2F%28%28x-2%29%28x-1%29%29%29\"
\n" ); document.write( "and you can multiply fully if desired.\r
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