document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969546>Question 969546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 41 years old and his son is 9. In how many years will the father be three times as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592405 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of years required.\r<BR>\n" );
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document.write( "Father is 41 +x at that time<BR>\n" );
document.write( "Son is 9 +x  at that time\r<BR>\n" );
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document.write( "Father is 3 times the son's age.\r<BR>\n" );
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document.write( "therefore 3(9+x)=41 +x<BR>\n" );
document.write( "Distribute the 3\r<BR>\n" );
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document.write( "27 +3x=41 +x\r<BR>\n" );
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document.write( "Subtract 27 from both sides\r<BR>\n" );
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document.write( "3x=14 +x<BR>\n" );
document.write( "Subtract x from both sides\r<BR>\n" );
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document.write( "2x=14<BR>\n" );
document.write( "Divide both sides by 2\r<BR>\n" );
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document.write( "x=7\r<BR>\n" );
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document.write( "In 7 years, the father will be 48<BR>\n" );
document.write( "In 7 years the son will be 16\r<BR>\n" );
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document.write( "48/16  = 3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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