document.write( "Question 967673: A restaurant prepares 22 litres of a mixture that contains 25% of orange essence and the remaining quantity as water. If 3 litres of water is mixed in this mixture,what will be the percentage of orange essence in the new mixture? \n" ); document.write( "
Algebra.Com's Answer #592400 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
First Stage:\r
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\n" ); document.write( "\n" ); document.write( "\"%2825x%2B0%2Ay%29%2F22=percentOrangeEssense\" of the mixture result.
\n" ); document.write( "Making the variable simpler on the right,
\n" ); document.write( "\"%2825x%29%2F22=p\"\r
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\n" ); document.write( "\n" ); document.write( "You do not yet have information for value of x nor y. NOR for p. You could still work with this using what variables and values you have.\r
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\n" ); document.write( "\n" ); document.write( "Stage Two:\r
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\n" ); document.write( "\n" ); document.write( "Add 3 liters of water, and find the new percent of the essense.\r
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\n" ); document.write( "\n" ); document.write( "\"22p%2F%2822%2B3%29\"
\n" ); document.write( "\"22%2825x%2F22%29%2F%2822%2B3%29\"
\n" ); document.write( "\"25x%2F%2825%29\"
\n" ); document.write( "\"x\"\r
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\n" ); document.write( "\n" ); document.write( "Give any improved problem description if you have it, because the solution here might be a misunderstanding of what your actual problem is.
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