document.write( "Question 969086: l2 kinds of coffee were mixed together, a jamaican coffee worth $5.40 a pound and a vanilla bean coffee worth $6.25 a pound. the mixture contained ten pound more than twice as much of the jamaican coffee. how much of each kind was used if the value of the mixture was $190.40 \n" ); document.write( "
Algebra.Com's Answer #592399 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You mean TWO kinds instead of TWELVE kinds.\r
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\n" ); document.write( "\n" ); document.write( "VARIABLES:
\n" ); document.write( "j, how much Jamaican Coffee
\n" ); document.write( "v, how much Vanilla Bean Coffee\r
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\n" ); document.write( "\n" ); document.write( "The description of j and v quantities,
\n" ); document.write( "10+2*what, ... the description falls apart.\r
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\n" ); document.write( "\n" ); document.write( "Continuing to try, the mixture is j+v.
\n" ); document.write( "\"j%2Bv=10%2B2%2Aj\", the mixture, IS, ten pounds more, than two times the amount of Jamaican coffee.
\n" ); document.write( "Simplify that is some useful way.
\n" ); document.write( "\"j%2Bv-v=10%2B2j-v\"
\n" ); document.write( "\"j=10%2B2j-v\"
\n" ); document.write( "\"j-2j=10%2B2j-v-2j\"
\n" ); document.write( "\"-j=10-v\"
\n" ); document.write( "\"highlight_green%28j=v-10%29\"-----we can work with this.\r
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\n" ); document.write( "\n" ); document.write( "Back to the fundamental two part mixture problem,\r
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\n" ); document.write( "\n" ); document.write( "\"cost%2Fmass=price\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%285.4%29j%2B%286.25%29v%29%2F%28j%2Bv%29=190.4%2F%28j%2Bv%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%285.4%29j%2B%286.25%29v=190.4\" because accounting for cost is really what is best here;\r
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\n" ); document.write( "\n" ); document.write( "Substitute according to the complicated description part, for j.
\n" ); document.write( "\"highlight_green%28%285.4%29%28v-10%29%2B%286.25%29v=190.4%29\"
\n" ); document.write( "A unsimplified linear equation in just the one variable, v.\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "and you know what to do from that.....?
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