document.write( "Question 969421: A fair sided coin is tossed 5 times\r
\n" );
document.write( "\n" );
document.write( "1) How many outcomes in the sample space
\n" );
document.write( "2) what is the probability that the third toss is heads given that that the first toss is heads
\n" );
document.write( "3) Let A be the event that the first toss is heads and B be the event that the third toss is heads. Are A and B independent, why or why not? \n" );
document.write( "
Algebra.Com's Answer #592324 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! There are 2 outcomes in the first toss, 4 in the second HH HT TH TT; 8 in the third, 16 in the 4th, and 32 in the 5th. Pascal's Triangle \n" ); document.write( "1 1 \n" ); document.write( "1 2 1 \n" ); document.write( "1 3 3 1 \n" ); document.write( "1 4 6 4 1 \n" ); document.write( "1 5 10 10 5 1 \n" ); document.write( " It doesn't show the triangular form formatted here, but notice how the top two add to the bottom one.\r \n" ); document.write( "\n" ); document.write( "There are 32 outcomes, if order matters, which it appears to in this question. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given that the first toss is heads, the probability the third toss is heads is 50%. They are independent. Whatever happened on the first toss has no effect on the third toss.\r \n" ); document.write( "\n" ); document.write( "Tree diagram hard to make here \n" ); document.write( "HT \n" ); document.write( "HH HT TH TT \n" ); document.write( "HHH HHT HTH HTT THH THT TTH TTT \n" ); document.write( "The first toss is heads (4), and you can see that the third toss is heads 50% of the time.\r \n" ); document.write( "\n" ); document.write( "If independent P(outcome 1)* P(outcome 2)= P (outcome 1 and outcome 2) \n" ); document.write( "P (1st toss is heads)=50% Probability third toss is heads is 50%. The first AND third should be heads 25% of the time. You can see 2 of the 8 above are, so they are independent. \n" ); document.write( " |