document.write( "Question 82635: Okay, I really need someone's help with this. I have asked everyone I know if they could help. And they CAN'T.\r
\n" ); document.write( "\n" ); document.write( "Solve the linear inequalities by graphing:\r
\n" ); document.write( "\n" ); document.write( "3x+4y<=12
\n" ); document.write( "x+3y<=6
\n" ); document.write( "x=>0
\n" ); document.write( "y=>0\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP!!!!
\n" ); document.write( "

Algebra.Com's Answer #59232 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"3x+%2B+4y+%3C=+12\"
\n" ); document.write( "\"x+%2B+3y+%3C=+6\"
\n" ); document.write( "\"x+%3E=+0\"
\n" ); document.write( "\"y+%3E=+0\"
\n" ); document.write( "Look at the 3rd and 4th first. \"x+%3E=+0\" simply says that x is
\n" ); document.write( "never negative. \"y+%3E=+0\" says y is never negative. The area
\n" ); document.write( "on the graph where both are true is the upper right quadrant, so
\n" ); document.write( "all solutions must be there as a restriction.
\n" ); document.write( "Solve the 1st and 2nd for y.
\n" ); document.write( "\"3x+%2B+4y+%3C=+12\"
\n" ); document.write( "\"4y+%3C=+12+-+3x\"
\n" ); document.write( "\"y+%3C=+3+-+%283%2F4%29x\"
\n" ); document.write( "-------------
\n" ); document.write( "\"x+%2B+3y+%3C=+6\"
\n" ); document.write( "\"3y+%3C=+6+-+x\"
\n" ); document.write( "\"y+%3C=+2+-+x%2F3\"
\n" ); document.write( "now plot these
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-2%2C+8%2C+-2%2C+8%2C+3+-+%283%2F4%29x%2C+2+-+x%2F3%29+\"
\n" ); document.write( "The solution is the area below the lines between (0,2) and (4,0)
\n" ); document.write( "Note that both these points are solutions and neither one
\n" ); document.write( "violates \"x+%3E=+0\" or \"y+%3E=+0\".
\n" ); document.write( "
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