document.write( "Question 969403:
\n" ); document.write( "A plane flew 1650 miles in 10 hours with the wind. The return trip took 11 hours, flying against the same wind. What was the speed of the wind?
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Algebra.Com's Answer #592302 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "1650=R*10
\n" ); document.write( "5-1650/10
\n" ); document.write( "R=165 MPH WITH THE WIND
\n" ); document.write( "1650=R*11
\n" ); document.write( "R=1650/11
\n" ); document.write( "R=150 AGAINST THE WIND
\n" ); document.write( "(165-150)/2=15/2
\n" ); document.write( "7.5 MPH IS THE WIND SPEED.
\n" ); document.write( "1650=(R+7.5)10
\n" ); document.write( "1650=10R+75
\n" ); document.write( "R=1650-75
\n" ); document.write( "10R=1575
\n" ); document.write( "R=1575/10
\n" ); document.write( "R=157.5 MPH FOR THR PLAN IN STILL AIR
\n" ); document.write( "PROOF:
\n" ); document.write( "1650=(157.5-7.5)11
\n" ); document.write( "1650=150*11
\n" ); document.write( "1650=1650\r
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