document.write( "Question 969403:
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document.write( "A plane flew 1650 miles in 10 hours with the wind. The return trip took 11 hours, flying against the same wind. What was the speed of the wind? \n" );
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Algebra.Com's Answer #592302 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "1650=R*10 \n" ); document.write( "5-1650/10 \n" ); document.write( "R=165 MPH WITH THE WIND \n" ); document.write( "1650=R*11 \n" ); document.write( "R=1650/11 \n" ); document.write( "R=150 AGAINST THE WIND \n" ); document.write( "(165-150)/2=15/2 \n" ); document.write( "7.5 MPH IS THE WIND SPEED. \n" ); document.write( "1650=(R+7.5)10 \n" ); document.write( "1650=10R+75 \n" ); document.write( "R=1650-75 \n" ); document.write( "10R=1575 \n" ); document.write( "R=1575/10 \n" ); document.write( "R=157.5 MPH FOR THR PLAN IN STILL AIR \n" ); document.write( "PROOF: \n" ); document.write( "1650=(157.5-7.5)11 \n" ); document.write( "1650=150*11 \n" ); document.write( "1650=1650\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |