document.write( "Question 969377: The perimeter of a rectangle is 100 cm and its diagonal is 32 cm find its area. \n" ); document.write( "
Algebra.Com's Answer #592290 by satyareddy22(84)\"\" \"About 
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Let l be length,b be breadth
\n" ); document.write( "perimeter of a rectangle = 100 cm
\n" ); document.write( "l+b=50cm-----------(1)
\n" ); document.write( "diagonal = 32 cm
\n" ); document.write( "By Pythagorean theorem l^2+b^2=32^2=1024-----(2)
\n" ); document.write( "Squaring eq (1)
\n" ); document.write( "=>(l+b)^2=50^2
\n" ); document.write( "=>l^2+b^2 +2lb=2500
\n" ); document.write( "from eq (2)
\n" ); document.write( "1024+2lb=2500
\n" ); document.write( "2lb=2500-1024=1476
\n" ); document.write( "lb=1476/2=738
\n" ); document.write( "lb=738,which is area of rectangle(lb)\r
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