document.write( "Question 969388: Find three consecutive odd positive integers such that 5 times the sum of all three is 66 more than the product of the first and second integers. \n" ); document.write( "

Algebra.Com's Answer #592276 by MathTherapy(10552) $\"\"$ $\"About$

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Find three consecutive odd positive integers such that 5 times the sum of all three is 66 more than the product of the first and second integers.
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Let the smallest integer be S
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document.write( "Then other 2 are: S + 2, and S + 4
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document.write( "We then get: 5(S + S + 2 + S + 4) = S(S + 2) + 66
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document.write( "(S - 9)(S - 4) = 0
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document.write( "S, or smallest integer =             OR          S = 4 (ignore)
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document.write( "Middle integer: 9 + 2, or 
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document.write( "Largest integer: 9 + 4, or  \n" );
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