document.write( "Question 969129: Ron has 15 coins with a total value of $2.55. The coins are nickels and quarters. How many of each does he have ? \n" ); document.write( "

Algebra.Com's Answer #592275 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "first kind of coin (in quotes)? nickel\r\n" );
document.write( "value of first kind of coin? .05\r\n" );
document.write( "second kind of coin in quotes)? quarter\r\n" );
document.write( "value of second kind of coin? .25\r\n" );
document.write( "number of coins? 15\r\n" );
document.write( "total value of coins? 2.55\r\n" );
document.write( "Let the number of nickels be x\r\n" );
document.write( "Then the number of quarters, using\r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 15-x.\r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
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document.write( "nickels      x        $0.05    $0.05x\r\n" );
document.write( "quarters   15-x       $0.25    $0.25(15-x)\r\n" );
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document.write( "TOTALS      15        -----    $2.55\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "     0.05x + 0.25(15-x) = 2.55\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100:\r\n" );
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document.write( "          5x + 25(15-x) = 255\r\n" );
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document.write( "         5x + 375 - 25x = 255\r\n" );
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document.write( "             -20x + 375 = 255\r\n" );
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document.write( "                   -20x = -120\r\n" );
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document.write( "                      x = 6 = the number of nickels.\r\n" );
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document.write( "The number of quarters is 15-x or 15-6 or 9 quarters.\r\n" );
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document.write( "Checking:  6 nickels is $0.30 and 9 quarters is $2.25\r\n" );
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document.write( "            And indeed $0.30 + $2.25 = $2.55\r\n" );
document.write( "Edwin

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