document.write( "Question 969388: Find three consecutive odd positive integers such that 5 times the sum of all three is 66 more than the product of the first and second integers. \n" ); document.write( "
Algebra.Com's Answer #592270 by josgarithmetic(39617)\"\" \"About 
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n is an integer.
\n" ); document.write( "First, 2n+1
\n" ); document.write( "Second, 2n+3
\n" ); document.write( "Third, 2n+5\r
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\n" ); document.write( "\n" ); document.write( "\"5%282n%2B1%2B2n%2B3%2B2n%2B5%29=66%2B%282n%2B1%29%282n%2B3%29\"
\n" ); document.write( "That is the description transcribed into an equation. \r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve for n, and then evaluate the three positive integers.
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