document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969361>Question 969361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tommy Recieved a 96 and an 80 his past two algebra 2 exams. If all exams are equally weighted, what score must he obtain on his 3rd exam to achieve a  grade average of 90 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592263 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Average grade of 90 for 3 exams means his total score must be 270, for (270/3)=90\r<BR>\n" );
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document.write( "He got a 96 and an 80.  They add to 176\r<BR>\n" );
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document.write( "270 (what he needs)- 176=94.\r<BR>\n" );
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document.write( "If he gets a 94, a 96, and a 80, he gets 270.  \r<BR>\n" );
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document.write( "Another way is he was +6 on the first exam and -10 on the second.  He is down 4.  He needs to be +4 on the third, and that is a 94. </SPAN>\n" );
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