document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82626>Question 82626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am completely lost on how to work this problem. solve:<BR>\n" );
document.write( "y-2-8sqrt(y-2)+15 = 0  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59226 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> get the sqrt term by itself and then square both sides ... y+13=8sqrt(y-2) ... (y+13)^2=64(y-2)\r<BR>\n" );
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document.write( "y^2+26y+169=64y-128 ... y^2-38y+297=0 ... factoring gives (y-27)(y-11)=0 ... y=27, y=11 </SPAN>\n" );
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