document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969294>Question 969294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and CHECK the system of equations by either substitution or addition method. PLEASE! SHOW ALL WORK AND EVERY STEP.  State what method you used and then show what  x and Y=\r<BR>\n" );
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document.write( "3x=-4y+15<BR>\n" );
document.write( "8y=-6x+30 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592205 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x=-4y+15 --> 3x + 4y = 15<BR>\n" );
document.write( "8y=-6x+30 --> 6x + 8y = 30<BR>\n" );
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document.write( "3x + 4y = 15<BR>\n" );
document.write( "6x + 8y = 30 Divide by 2 --> 3x + 4y = 15<BR>\n" );
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document.write( "3x + 4y = 15<BR>\n" );
document.write( "3x + 4y = 15<BR>\n" );
document.write( "-------------------- Subtract (elimination)<BR>\n" );
document.write( "0 = 0<BR>\n" );
document.write( "It's the same equation twice --> dependent.<BR>\n" );
document.write( "No unique solution.<BR>\n" );
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