document.write( "Question 969172: You have been asked to design a can shaped like a right circular cylinder with height h and radius r. Given that the can must hold exactly 410 cm^3, what values of h and r will minimise the total surface area (including the top and bottom faces)? Give your answers correct to 2 decimal places as a list [in brackets] of the form: [ h, r ]
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document.write( "for constants h (height), r (radius), in that order.\r
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Algebra.Com's Answer #592171 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i couldn't find any other way to do it without using calculus, so i solved it by graphing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i got r = 4.025946 and h = 8.051894821.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with those values, surface area = 2 * pi * r * h + 2 * p * r^2 = 305.51822\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of the equation for surface area looks like this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for surface area used was:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 2 * pi * x * (410/(pi * x^2)) + 2 * pi * x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y represents the surface area. \n" ); document.write( "x represents the radius. \n" ); document.write( "h is equal to (410 / (pi * r^2))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this was derived by solving for h in the volume formuls of v = pi * r^2 * h.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when v is equal to 410, this formula became 410 = pi * r^2 * h.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this led to h = (410 / (pi * r^2)).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula could have been simplified further but i left it the way it was so you could see the value of h in terms of r stand out more clearly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area on the graph of interest is when x and y are both greater than 0.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |