document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969245>Question 969245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this problem is so difficult can someone please help me out :) thanks\r<BR>\n" );
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document.write( "A circular cone having an altitude of 9m is divided into two segments having the same vertex . if the smaller altitude is 6m , find the ratio of the volume of the small cone to the big cone  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592156 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circular cone having an altitude of 9m is divided into two segments having the same vertex . if the smaller altitude is 6m , find the ratio of the volume of the small cone to the big cone<BR>\n" );
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document.write( "Note: The ratio of the radii of the bases of the two cones is 9:6 or 3/2<BR>\n" );
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document.write( "Volume of big cone = (1/3)pi*r^2*9<BR>\n" );
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document.write( "Volume of smaller cone = (1/3)pi(2/3 r)^2*6 = (1/3)pi*r^2[(4/9)*6]<BR>\n" );
document.write( "= (1/3)pi*r^2[8/3)<BR>\n" );
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document.write( "Ans: ratio of volumes = [Vol of small]/[Vol of bigger]<BR>\n" );
document.write( "= (8/3)/9 = 8/27 = 8:27<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  <BR>\n" );
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