document.write( "Question 969153: What are the tecniques to isolate y on x^2+y^2-2y=0?
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Algebra.Com's Answer #592099 by MathLover1(20855)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "to isolate \"y\" on \"x%5E2%2By%5E2-2y=0\", move \"x%5E2\" to the right and complete the square for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2-2y=0-x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%5E2-2y%2B_%29-_=-x%5E2\"....recall the rule \"a%5E2-2ab%2Bb%5E2=%28a-b%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "in your case \"a=1\" and \"2ab=2\"=>\"2%2A1b=2\"=>\"b=1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%5E2-2y%2B1%29-1=-x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y-1%29%5E2-1=-x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y-1%29%5E2=-x%5E2%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"y-1=sqrt%28-x%5E2%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=sqrt%28-x%5E2%2B1%29%2B1\"\r
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