document.write( "Question 82567: If f(x) = x(x + 1)(x - 4), use interval notation to give all values of x where f(x)> 0. \n" ); document.write( "
Algebra.Com's Answer #59209 by Nate(3500) ![]() You can put this solution on YOUR website! x(x + 1)(x - 4) \n" ); document.write( "Zeros (x - intercepts) \n" ); document.write( "x = 0 \n" ); document.write( "x = -1 \n" ); document.write( "x = 4\r \n" ); document.write( "\n" ); document.write( "f(x) > 0 \n" ); document.write( "x(x + 1)(x - 4) > 0\r \n" ); document.write( "\n" ); document.write( "X-Axis \n" ); document.write( "<---------(-1)-------(0)-------------------(4)--------------->\r \n" ); document.write( "\n" ); document.write( "Test: x = -2 \n" ); document.write( "(-2)(-2 + 1)(-2 - 4) > 0 \n" ); document.write( "(-2)(-1)(-6) > 0 \n" ); document.write( "-12 > 0 False\r \n" ); document.write( "\n" ); document.write( "Test: x = -0.5 \n" ); document.write( "(-0.5)(-0.5 + 1)(-0.5 - 4) > 0 \n" ); document.write( "(-0.5)(0.5)(-4.5) > 0 \n" ); document.write( "1.125 > 0 True\r \n" ); document.write( "\n" ); document.write( "Test: x = 1 \n" ); document.write( "(1)(1 + 1)(1 - 4) > 0 \n" ); document.write( "(1)(2)(-3) > 0 \n" ); document.write( "-6 > 0 False\r \n" ); document.write( "\n" ); document.write( "Test: x = 5 \n" ); document.write( "(5)(5 + 1)(5 - 4) > 0 \n" ); document.write( "(5)(6)(1) > 0 \n" ); document.write( "30 > 0 True\r \n" ); document.write( "\n" ); document.write( "X-Axis \n" ); document.write( "<---------(-1)========(0)-------------------(4)==============> \n" ); document.write( "(-1,0)U(4,+ \n" ); document.write( "\n" ); document.write( "Proof:\r \n" ); document.write( "\n" ); document.write( " |