document.write( "Question 969123: how do i write an equation for Line p contains point (6,-5) and is perpendicular to line q. The equation for line q is y = 3x + 5. \n" ); document.write( "
Algebra.Com's Answer #592081 by stanbon(75887)\"\" \"About 
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how do i write an equation for Line p contains point (6,-5) and is perpendicular to line q. The equation for line q is y = 3x + 5.
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\n" ); document.write( "Line q has slope = 3
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\n" ); document.write( "Any line perpendicular to q must have slope = -1/3
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\n" ); document.write( "Form::
\n" ); document.write( "y = mx + b
\n" ); document.write( "Solve for \"b\"::
\n" ); document.write( "-5 = (-1/3)6 + b
\n" ); document.write( "-5 = -2 + b
\n" ); document.write( "b = -3
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\n" ); document.write( "Equation you want::
\n" ); document.write( "y = (-1/3)x - 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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