document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82492>Question 82492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So Iwould like to just check my answer to this problem. What did you get? A load of 8kg attached to the bottom of a coil spring stretches the spring to a length of 76 cm, and a load of 14kg stretches it to a length of 85cm. Find the natural (unstretched) length of the spring.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59208 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59208\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the distance a spring stretches is directly proportional to the load (or force) on the spring x=kf\r<BR>\n" );
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document.write( "let L equal the unstretched length ... so L+8k=76 ... and L+14k=85\r<BR>\n" );
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document.write( "multiplying the first equation by 7/4 and subtracting the second equation gives (7/4)L+14k-(L+14K)=(7/4)76-85\r<BR>\n" );
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document.write( "so (3/4)L=48 ... L=64 cm </SPAN>\n" );
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