document.write( "Question 82594: solve the system by addition, \r
\n" ); document.write( "\n" ); document.write( "x+y=2
\n" ); document.write( "x-y=4\r
\n" ); document.write( "\n" ); document.write( "5x-3y=13
\n" ); document.write( "4x-3y=11
\n" ); document.write( "

Algebra.Com's Answer #59206 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Lets start with \r
\n" ); document.write( "\n" ); document.write( "\"x%2By=2\"
\n" ); document.write( "\"x-y=4\"\r
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%2Ay=2\"
\n" ); document.write( " \"1%2Ax-1%2Ay=4\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 1 and 1 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 1 and 1 is 1, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -1 like this:
\n" ); document.write( "
\n" ); document.write( " \"1%2A%281%2Ax%2B1%2Ay%29=%282%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-1%2A%281%2Ax-1%2Ay%29=%284%29%2A-1\" Multiply the bottom equation (both sides) by -1
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"1%2Ax%2B1%2Ay=2\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=-4\"
\n" ); document.write( "
\n" ); document.write( " Notice how 1 and -1 add to zero (ie \"1%2B-1=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%281%2Ax-1%2Ax%29%2B%281%2Ay%2B1%2Ay%29=2-4\"
\n" ); document.write( "
\n" ); document.write( " \"%281-1%29%2Ax%2B%281%2B1%29y=2-4\"
\n" ); document.write( "
\n" ); document.write( " \"cross%281%2B-1%29%2Ax%2B%281%2B1%29%2Ay=2-4\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"2%2Ay=-2\"
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2F2\" Divide both sides by \"2\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
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\n" ); document.write( " \"y=-1\" Reduce
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\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"1%2Ax%2B1%2Ay=2\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%28-1%29=2\" Plug in \"y=-1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-1=2\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=2%2B1\" Subtract \"-1\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=3\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ax=%283%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out \"1\" on the left side.
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\n" ); document.write( "
\n" ); document.write( " \"x=3\" Multiply the terms on the right side
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\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=3\", \"y=-1\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"3\", \"-1\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%2Ay=2\"
\n" ); document.write( " \"1%2Ax-1%2Ay=4\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=2\" (red) \"1%2Ax-1%2Ay=4\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"3\",\"-1\"). This verifies our answer.

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\n" ); document.write( "\n" ); document.write( "Now lets solve \r
\n" ); document.write( "\n" ); document.write( "\"5x-3y=13\"
\n" ); document.write( "\"4x-3y=11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B3%2Ay=13\"
\n" ); document.write( " \"4%2Ax-3%2Ay=11\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 4 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 5 and 4 is 20, we need to multiply both sides of the top equation by 4 and multiply both sides of the bottom equation by -5 like this:
\n" ); document.write( "
\n" ); document.write( " \"4%2A%285%2Ax%2B3%2Ay%29=%2813%29%2A4\" Multiply the top equation (both sides) by 4
\n" ); document.write( " \"-5%2A%284%2Ax-3%2Ay%29=%2811%29%2A-5\" Multiply the bottom equation (both sides) by -5
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"20%2Ax%2B12%2Ay=52\"
\n" ); document.write( " \"-20%2Ax%2B15%2Ay=-55\"
\n" ); document.write( "
\n" ); document.write( " Notice how 20 and -20 add to zero (ie \"20%2B-20=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2820%2Ax-20%2Ax%29%2B%2812%2Ay%2B15%2Ay%29=52-55\"
\n" ); document.write( "
\n" ); document.write( " \"%2820-20%29%2Ax%2B%2812%2B15%29y=52-55\"
\n" ); document.write( "
\n" ); document.write( " \"cross%2820%2B-20%29%2Ax%2B%2812%2B15%29%2Ay=52-55\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"27%2Ay=-3\"
\n" ); document.write( "
\n" ); document.write( " \"y=-3%2F27\" Divide both sides by \"27\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-1%2F9\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"5%2Ax%2B3%2Ay=13\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B3%28-1%2F9%29=13\" Plug in \"y=-1%2F9\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax-3%2F9=13\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax-1%2F3=13\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax=13%2B1%2F3\" Subtract \"-1%2F3\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax=39%2F3%2B1%2F3\" Make 13 into a fraction with a denominator of 3
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax=40%2F3\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F5%29%285%29%29%2Ax=%2840%2F3%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=8%2F3\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=8%2F3\", \"y=-1%2F9\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"8%2F3\", \"-1%2F9\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B3%2Ay=13\"
\n" ); document.write( " \"4%2Ax-3%2Ay=11\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"5%2Ax%2B3%2Ay=13\" (red) \"4%2Ax-3%2Ay=11\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"8%2F3\",\"-1%2F9\"). This verifies our answer.

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