document.write( "Question 968954: I am having trouble trying to solve this problem. I would be very grateful if you could explain to me the steps in finding the answers. \r
\n" ); document.write( "\n" ); document.write( "Solve each system using any method: [referring to substitution and elimination] \r
\n" ); document.write( "\n" ); document.write( "3x-2y-3z=0
\n" ); document.write( "x-3y+z=10
\n" ); document.write( "2x+2y-4z=-10 \r
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\n" ); document.write( "\n" ); document.write( "Thank you so much.
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Algebra.Com's Answer #592014 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
3x - 2y - 3z = 0
\n" ); document.write( "x - 3y + z = 10
\n" ); document.write( "2x + 2y -4z =-10
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by -1 to change the signs
\n" ); document.write( "-3x + 2y +3z = 0
\n" ); document.write( "x - 3y + z = 10
\n" ); document.write( "2x + 2y -4z =-10
\n" ); document.write( "-------------------Addition eliminates x and z
\n" ); document.write( " 0 + y + 0 = 0
\n" ); document.write( "y = 0
\n" ); document.write( "Back to the 1st equation replace y with 0 and you have
\n" ); document.write( "3x - 3z = 0
\n" ); document.write( "3x = 3z
\n" ); document.write( "divide both sides by 3, therefore
\n" ); document.write( "x = z
\n" ); document.write( "Back to the 3rd original equation, replace z with x and y with 0
\n" ); document.write( "2x - 4x = - 10
\n" ); document.write( "-2x = -10
\n" ); document.write( "x = -10/-2
\n" ); document.write( "x = +5
\n" ); document.write( "Therefore
\n" ); document.write( "z = 5 also
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\n" ); document.write( "We have x=5, y=0, z=5
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\n" ); document.write( "See if that checks out in the 2nd original equation
\n" ); document.write( "x - 3y + z = 10
\n" ); document.write( "replace x with 5, y with 0, z with 5
\n" ); document.write( "5 - 0 + 5 = 10
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