document.write( "Question 968762: The volume of a cone is 3000 whath appens to the volume if u double the diameter
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Algebra.Com's Answer #591932 by Theo(13342)\"\" \"About 
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v1 = 1/3 * pi * r^2 * h\r
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\n" ); document.write( "\n" ); document.write( "if you double the diameter, then you are doubling the radius as well.\r
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\n" ); document.write( "\n" ); document.write( "v2 = 1/3 * pi * (2r)^2 * h\r
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\n" ); document.write( "\n" ); document.write( "simplify this to get:\r
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\n" ); document.write( "\n" ); document.write( "v2 = 1/3 * pi * 4 * r^2 * h\r
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\n" ); document.write( "\n" ); document.write( "divide v2 by v1 to get:\r
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\n" ); document.write( "\n" ); document.write( "v2 / v1 = (1/3 * pi * 4 * r^2 * h) / (1/3 * pi * r^2 * h)\r
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\n" ); document.write( "\n" ); document.write( "simplify to get v2 / v1 = 4\r
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\n" ); document.write( "\n" ); document.write( "the volume will be 4 times as large.\r
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\n" ); document.write( "\n" ); document.write( "if v1 = 3000, then v2 = 12000.\r
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