document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968769>Question 968769</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A is now three times older than B. In 5 years A will be twice as old as B will be then. Find their present ages.\r<BR>\n" );
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document.write( "I am an English teacher tutoring math and can't remember how to do this one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591930 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 3B<BR>\n" );
document.write( "A +5 = 2(B +5)<BR>\n" );
document.write( "A +5 = 2B +10<BR>\n" );
document.write( "now substitute for A = 3B<BR>\n" );
document.write( "3B +5 = 2B +10<BR>\n" );
document.write( "subtract 2B form both sides of =<BR>\n" );
document.write( "B +5 = 10<BR>\n" );
document.write( "B = 5 and A = 15<BR>\n" );
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document.write( "check answer by substituting for A and B in the second equation<BR>\n" );
document.write( "15 +5 = 2(5+5)<BR>\n" );
document.write( "20 = 20<BR>\n" );
document.write( "our answer checks<BR>\n" );
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