document.write( "Question 82604: solve for real roots: sqrt(2x^2+x-12)=x\r
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document.write( "this is not a text book, just on paper, I do not understand it \n" );
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Algebra.Com's Answer #59193 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(2x^2+x-12)=x \n" ); document.write( "Square both sides to get: \n" ); document.write( "2x^2+x-12 = x^2 \n" ); document.write( "x^2+x-12 = 0 \n" ); document.write( "(x+4)(x-3)=0 \n" ); document.write( "x= -4 or x=3 \n" ); document.write( "Checking in the original equation: \n" ); document.write( "If x=-4: sqrt(32-4-12)=sqrt16 = -4 \n" ); document.write( "No; that is wrong so x=-4 is not a solution. \n" ); document.write( "---------- \n" ); document.write( "sqrt(2*9+3-12)= sqrt(9)=3 \n" ); document.write( "Right; x=3 is a solution. \n" ); document.write( "=========== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |