document.write( "Question 82604: solve for real roots: sqrt(2x^2+x-12)=x\r
\n" ); document.write( "\n" ); document.write( "this is not a text book, just on paper, I do not understand it
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Algebra.Com's Answer #59193 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sqrt(2x^2+x-12)=x
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "2x^2+x-12 = x^2
\n" ); document.write( "x^2+x-12 = 0
\n" ); document.write( "(x+4)(x-3)=0
\n" ); document.write( "x= -4 or x=3
\n" ); document.write( "Checking in the original equation:
\n" ); document.write( "If x=-4: sqrt(32-4-12)=sqrt16 = -4
\n" ); document.write( "No; that is wrong so x=-4 is not a solution.
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\n" ); document.write( "sqrt(2*9+3-12)= sqrt(9)=3
\n" ); document.write( "Right; x=3 is a solution.
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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