document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968565>Question 968565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the expression.<BR>\n" );
document.write( "(5/6)log&#119909;+(2/3)log&#119910;&#8722;(1/2)log&#119909;&#8722;log&#119910;\r<BR>\n" );
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document.write( "I know that the answer is log cube root of (x/y) but I'm not sure how to get to that answer.  Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591902 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify the expression.<BR>\n" );
document.write( "(5/6)log&#119909;+(2/3)log&#119910;&#8722;(1/2)log&#119909;&#8722;log&#119910; <BR>\n" );
document.write( "log(x^(5/6)y^(2/3)/x^(1/2)y)<BR>\n" );
document.write( "log(x^1/3/y^1/3)<BR>\n" );
document.write( "log(x/y)^1/3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28root%283%2Cx%2Fy%29%29 ALIGN=MIDDLE  ALT=\"log%28root%283%2Cx%2Fy%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >                                                                                                  </SPAN>\n" );
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