document.write( "Question 968670: At what interest rate will $500 grow to $572.45 on 2 yrs?\r
\n" ); document.write( "\n" ); document.write( "using A = P(1+r)^2 \n" ); document.write( "

Algebra.Com's Answer #591894 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "At what interest rate will $ $\"500\"$ grow to $ $\"572.45\"$ on $\"2\"$ yrs?
\n" ); document.write( "using $\"A+=+P%281%2Br%29%5E2\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"572.45+=+500%281%2Br%29%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"572.45%2F+500=%281%2Br%29%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1.1449=%281%2Br%29%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%281.1449%29=sqrt%28%281%2Br%29%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%281.1449%29=1%2Br\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1.07=1%2Br\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1.07-1=r\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"r=0.07\"$ or $\"7\"$ %\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "first year $\"500%2B500%2A0.07=500%2B35=535\"$
\n" ); document.write( "second year $\"535%2B535%2A0.07=535%2B37.45=572.45\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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