document.write( "Question 968545: \r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 5 ft more than twice the width, and the area of the rectangle is 63 ft^2Find the dimensions of the rectangle.
\n" ); document.write( "Length: _ft Width: _ft
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Algebra.Com's Answer #591873 by checkley77(12844)\"\" \"About 
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AREA=63
\n" ); document.write( "L=2W+5
\n" ); document.write( "AREA=LW
\n" ); document.write( "63=(2W+5)*W
\n" ); document.write( "63=2W^2+5W
\n" ); document.write( "2W^+5W-63=0
\n" ); document.write( "(2W-9)(W+7)=0
\n" ); document.write( "2W-9=0
\n" ); document.write( "W=9/2
\n" ); document.write( "W=4.5 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*4.5+5
\n" ); document.write( "L=9+5
\n" ); document.write( "L=14 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "63=14*4.5
\n" ); document.write( "63=63
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