document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968273>Question 968273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how i can locate 2pi/5 on a unit circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591856 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The entire unit circle would have a measure of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi ALIGN=MIDDLE  ALT=\"2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > radians. <BR>\n" );
document.write( "So (1/5) of that would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282pi%29%2F5 ALIGN=MIDDLE  ALT=\"%282pi%29%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "So break up the circle into 5 equi-angular slices. <BR>\n" );
document.write( "In degrees it would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%2F5=72 ALIGN=MIDDLE  ALT=\"360%2F5=72\"   DISABLED_style= \"max-width:90%; height:auto;\" >, every 72 degrees.<BR>\n" );
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