document.write( "Question 968553: the sum of the digits of a two digit number is 12. of the digits are reversed, the new number is 4/5 times of original number. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #591849 by josgarithmetic(39630)\"\" \"About 
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u and t;
\n" ); document.write( "10u+t is the number.
\n" ); document.write( "u+t=12.\r
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\n" ); document.write( "\n" ); document.write( "Reversed, the number is 10t+u.
\n" ); document.write( "(10u+t)=(4/5)(10t+u).\r
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\n" ); document.write( "\n" ); document.write( "Solve the system
\n" ); document.write( "\"system%28u%2Bt=12%2C10u%2Bt=%284%2F5%29%2810t%2Bu%29%29\".
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