document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968493>Question 968493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 1260m^2 Find the dimensions of the rectangle if we know that one side is 48 m longer than three times the other side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591818 by </B><A HREF=/tutors/aboutme.mpl?userid=sumairazzaq><B>sumairazzaq(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sumairazzaq><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sumairazzaq><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 1260 m^2<BR>\n" );
document.write( "Area = L*W = 1260 .......1<BR>\n" );
document.write( "Condition<BR>\n" );
document.write( "L = 48 + 3W <BR>\n" );
document.write( "Put in 1<BR>\n" );
document.write( "(48+3W)W=1260<BR>\n" );
document.write( "(16+W)W=420<BR>\n" );
document.write( "W^2+W-420 =0<BR>\n" );
document.write( "W=14, -30<BR>\n" );
document.write( "Length is alwys +ve<BR>\n" );
document.write( "So W=14<BR>\n" );
document.write( "L =90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );