document.write( "Question 968426: 2sec^2 x-7 sec x+6=0 \n" ); document.write( "

Algebra.Com's Answer #591783 by lwsshak3(11628) $\"\"$ $\"About$

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2sec^2 x-7 sec x+6=0
\n" ); document.write( "(2secx-3)(secx-2)=0
\n" ); document.write( "secx=3/2
\n" ); document.write( "cosx=2/3
\n" ); document.write( "x=48.19˚
\n" ); document.write( "or
\n" ); document.write( "secx=2
\n" ); document.write( "cosx=1/2
\n" ); document.write( "x=60˚ \n" ); document.write( "

\n" );