document.write( "Question 968366: Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).\r
\n" ); document.write( "\n" ); document.write( "The test statistic in a left-tailed test is z = -2.05
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Algebra.Com's Answer #591751 by stanbon(75887)\"\" \"About 
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Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
\n" ); document.write( "The test statistic in a left-tailed test is z = -2.05
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\n" ); document.write( "p-value = p(z < -2.05) = normalcdf(-100,-2.05) = 0.0218
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\n" ); document.write( "Since the p-value is less than 5%, reject Ho.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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