document.write( "Question 968363: Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). \r
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document.write( "With H1: p> 0.299, the test statistic is z = 1.12 \n" );
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Algebra.Com's Answer #591740 by stanbon(75887) ![]() You can put this solution on YOUR website! Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). \n" ); document.write( "With H1: p> 0.299, the test statistic is z = 1.12 \n" ); document.write( "------- \n" ); document.write( "p-value = P(z > 1.12) = normalcdf(1.12,100) = 0.1314 \n" ); document.write( "---- \n" ); document.write( "Since the p-value is greater than 5%, fail to reject Ho. \n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |