document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968188>Question 968188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591681 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "int + int = interest<BR>\n" );
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document.write( "0.10x + 0.08(80,000-x) = 7800<BR>\n" );
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document.write( "10x + 8*80000 - 8x = 780000<BR>\n" );
document.write( "2x = 780000-640000<BR>\n" );
document.write( "2x = 120000<BR>\n" );
document.write( "x = $60,000 (amt. invested at 10%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( " </SPAN>\n" );
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