document.write( "Question 82555: The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 56 in., find the width of the rectangle.\r
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Algebra.Com's Answer #59166 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=width
\n" ); document.write( "Then 2x+4=length\r
\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle =2W+2L. So:\r
\n" ); document.write( "\n" ); document.write( "2x+2(2x+4)=56 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "2x+4x+8=56 subtract 8 from both sides
\n" ); document.write( "2x+4x+8-8=56-8 collect like terms\r
\n" ); document.write( "\n" ); document.write( "6x=48 divide both sides by 6
\n" ); document.write( "x=8 in--------------------------------width
\n" ); document.write( "2x+4=2*8+4=20 in--------------------length\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "Perimeter equals 56 in\r
\n" ); document.write( "\n" ); document.write( "2(8)+2(20)=56\r
\n" ); document.write( "\n" ); document.write( "16+40=56
\n" ); document.write( "56=56\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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