document.write( "Question 967997: Good evening! Can someone walk me through this, please?
\n" ); document.write( "For the following equation of a parabola determine the vertex, focus, and directrix:
\n" ); document.write( "y2+2x−8y+7=1
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Algebra.Com's Answer #591648 by lwsshak3(11628)\"\" \"About 
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For the following equation of a parabola determine the vertex, focus, and directrix:
\n" ); document.write( "y2+2x−8y+7=1
\n" ); document.write( "y^2-8y+2x=-6
\n" ); document.write( "complete the square:
\n" ); document.write( "(y^2-8y+16)-16+2x=-6
\n" ); document.write( "(y-4)^2=-2x+10
\n" ); document.write( "(y-4)^2=-2(x-5)
\n" ); document.write( "This is an equation of a parabola that opens leftward
\n" ); document.write( "Its basic form of equation: (y-k)^2=4p(x-h), (h,k)=coordinates of vertex
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex: (5, 4)
\n" ); document.write( "axis of symmetry: y=4
\n" ); document.write( "4p=2
\n" ); document.write( "p=1/2
\n" ); document.write( "focus:(4.5,4) (p-distance left of vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=5.5 (p-distance right of vertex on the axis of symmetry)
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