document.write( "Question 82580: Lane invested $22,000 part at 8% and part at 7%. If the actual interest at the end of the year is $1710. How much did she invest at 8%?\r
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document.write( "(a)$18,000
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document.write( "(b)$16,000
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document.write( "(c)$5,000
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document.write( "(d)$17,000 \n" );
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Algebra.Com's Answer #59163 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x=amount invested at 8%\r \n" ); document.write( "\n" ); document.write( "Then $22000-x=amount invested at 7%\r \n" ); document.write( "\n" ); document.write( "Interest(I)=Principal(P) times Rate(R) times time(T) or I=PRT \r \n" ); document.write( "\n" ); document.write( "Interest on amount invested at 8%= 0.08x \n" ); document.write( "Interest on amount invested at 7%= 0.07($22000-x)\r \n" ); document.write( "\n" ); document.write( "Now we are told that the actual interest at the end of the year is $1710. So:\r \n" ); document.write( "\n" ); document.write( "0.08x+0.07($22000-x)=$1710 get rid of parens\r \n" ); document.write( "\n" ); document.write( "0.08x+$1540-0.07x=$1710 subtract $1540 from both sides\r \n" ); document.write( "\n" ); document.write( "0.08x+$1540-$1540-0.07x=$1710-$1540 collect like terms\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.01x=$170 divide both sides by 0.01\r \n" ); document.write( "\n" ); document.write( "x=$17000-------------------------amount invested at 8%\r \n" ); document.write( "\n" ); document.write( "$22000-x=$22000-$17000=$5000 -----------amount invested at 7%\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "$5000(0.07)+$17000(0.08)=$1710\r \n" ); document.write( "\n" ); document.write( "$350+$1360=$1710\r \n" ); document.write( "\n" ); document.write( "$1710=$1710\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |