document.write( "Question 968003: Hello, I'm looking for some guidance with this question, can anyone help?\r
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document.write( "For the following equation of a hyperbola determine the center, vertices, foci, and asymptotes:
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document.write( "36x^2−y^2−24x+6y−41=0 \n" );
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Algebra.Com's Answer #591624 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! For the following equation of a hyperbola determine the center, vertices, foci, and asymptotes: \n" ); document.write( " 36x^2−y^2−24x+6y−41=0 \n" ); document.write( "36(x^2-(24/36)x) - (y^2-6y) = 41 \n" ); document.write( "----- \n" ); document.write( "Complete the square:: \n" ); document.write( "36(x^2 - (2/3)x + (1/3)^2) - (y^2-6y+9) = 41 + 36(1/9) - 9 \n" ); document.write( "------ \n" ); document.write( "36(x-(1/3)^2 - (y-3)^2 = 36 \n" ); document.write( "------ \n" ); document.write( "Rewrite: \n" ); document.write( "(x-(1/3))^2 - (y-3)^2/36 = 1 \n" ); document.write( "a = 6 ; b = 1 ; c = sqrt(36+1) = sqrt(37) \n" ); document.write( "------------------------------------- \n" ); document.write( "center: (1/3, 3) \n" ); document.write( "vertices:: (1/3,3-6);(1/3,3+6) \n" ); document.write( "------------------ \n" ); document.write( "foci:: ((1/3),-3-sqrt(37)),((1/3),9+sqrt(37)) \n" ); document.write( "----- \n" ); document.write( "asymptotes: I'll leave that to you \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |