document.write( "Question 82575: The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 56 in., find the width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Answer: The width is ______ \r
\n" ); document.write( "\n" ); document.write( "Show work:
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #59161 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
Formula for the perimeeter of a rectangle:
\n" ); document.write( "P=2[(length + width)]
\n" ); document.write( "P=56
\n" ); document.write( "Length=2w+4
\n" ); document.write( "Width=w
\n" ); document.write( ".
\n" ); document.write( "so,
\n" ); document.write( "56=2[(2w+4)+w)]
\n" ); document.write( "56/2=2/2(2w+4+w)]
\n" ); document.write( "28=3w+4
\n" ); document.write( "28-4=3w
\n" ); document.write( "24=3w
\n" ); document.write( "24/3=3w/3
\n" ); document.write( "8=w
\n" ); document.write( ".
\n" ); document.write( "So,
\n" ); document.write( "P=56
\n" ); document.write( "Length=2w+4 = 2(8)+4=16+4=20
\n" ); document.write( "Width=w=8
\n" ); document.write( ".
\n" ); document.write( "Plugging everything back into the formula for a perimeter:
\n" ); document.write( "P=2[(length + width)]
\n" ); document.write( "56=2(20+8)
\n" ); document.write( "56=2(28)
\n" ); document.write( "56=56 [checks out]
\n" ); document.write( " \n" ); document.write( "
\n" );