document.write( "Question 967984: susan paid .49 per page for color copy and .9 per page for black and white copy. If susn bill for 90 copies was $12.90. How may copies of each type were made
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #591607 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "C=number of color copies; B=number of black and white copies \n" ); document.write( "B+C=90 \n" ); document.write( "B=90-C Use this to substitute for B. \n" ); document.write( "$0.09B+$0.49C=$12.90 Substitute for B. \n" ); document.write( "$0.09(90-C)+$0.49C=$12.90 \n" ); document.write( "$8.10-$0.09C+$0.49C=$12.90 Subtract $8.10 from each side. \n" ); document.write( "$0.40C=$4.80 Divide each side by $0.40 \n" ); document.write( "C=12 ANSWER 1: There were 12 color copies. \n" ); document.write( "B=90-C=90-12=78 ANSWER 2: There were 78 black and white copies. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "$0.09B+$0.49C=$12.90 \n" ); document.write( "$0.09(78)+$0.49(12)=$12.90 \n" ); document.write( "$7.02+$5.88=$12.90 \n" ); document.write( "$12.90=$12.90 \n" ); document.write( " |