document.write( "Question 967961: A32 year old mother realized that her age is twice the sum of her two children's age. Her son jose is two years older than.her daughter sophia. \n" ); document.write( "

Algebra.Com's Answer #591592 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "S=Sophia's age; J=Jose's age=S+2yrs
\n" ); document.write( "2(S+J)=32 years Substitute for J
\n" ); document.write( "2(S+S+2yrs)=32 years
\n" ); document.write( "2(2S+2yrs)=32 years
\n" ); document.write( "4S+4yrs=32 years Subtract 4 years from each side.
\n" ); document.write( "4S=28 years Divide each side by 4
\n" ); document.write( "S=7 years ANSWER 1: Sophia is 7 years old.
\n" ); document.write( "J=S+2yrs=7yrs+2yrs=9yrs ANSWER 2: Jose is 9 years old.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "2(S+J)=32 years
\n" ); document.write( "2(7yrs+9yrs)=32 years
\n" ); document.write( "2(16yrs)=32 years
\n" ); document.write( "32 years=32 years
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