document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967951>Question 967951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sarah is 5 years older than her sister hanna. Jim is twice as old as his sister hanna. Thier combined age is 74. Write an equation that can be used to find their ages </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591588 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "A single equation cannot be written that is solvable for three variables.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "H=Hanna's age; S=Sarah's age=H+5; J=Jim's age=2H<BR>\n" );
document.write( "H+S+J=74 years Substitute for S and J.<BR>\n" );
document.write( "H+(H+5)+2H=74 years<BR>\n" );
document.write( "4H+5=74 years Subtract 5 years from each side.<BR>\n" );
document.write( "4H=69 years Divide each side by 4<BR>\n" );
document.write( "H=17.25 years ANSWER 1: Hannah is 17.25 years old.<BR>\n" );
document.write( "S=H+5yrs=17.25 years+5 years=22.25 years ANSWER 2: Sarah is 22.25 years old.<BR>\n" );
document.write( "J=2H=2(17.25 years)=34.5 years ANSWER 3: Jim is 34.5 years old.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "H+S+J=74 years<BR>\n" );
document.write( "17.25 years+22.25 years+34.5years=74 years<BR>\n" );
document.write( "74 years=74 years  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );