document.write( "Question 82569: Solve the system by addition:\r
\n" ); document.write( "\n" ); document.write( "-5x+2y=10
\n" ); document.write( "x-3y=11
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Algebra.Com's Answer #59157 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Linear Systems by Addition
We'll solve the system:
\n" ); document.write( " \"-5%2Ax+%2B+2%2Ay+=+10\"
\n" ); document.write( " \"1%2Ax+%2B+-3%2Ay+=+11\"
\n" ); document.write( " by elimination by addition.To eliminate by addition, we need to set both coefficients of x to numbers with changed signs, i.e a and -a. Since in the second equation we have 1 as our coefficient for x, to get 5 we have to multiply all terms of the second equation by \"5%2F1\" which is equal to 5.
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\n" ); document.write( " Multiplying, we get on our second equation:\"%281%2A5%29x+%2B+%28-3%2A5%29y+=+11%2A5\"
\n" ); document.write( " \"5%2Ax+%2B+-15%2Ay+=+55\"
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\n" ); document.write( " Adding both equations we get:
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\n" ); document.write( " \"%28-5%2B5%29x+%2B+%282%2B-15%29y+=+%2810%2B55%29\"
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\n" ); document.write( " Since -5 and 5 cancel out, we have a linear equation:Therefore, we know that y = -5.
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\n" ); document.write( " Plugging that in into the first equation gives us:
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\n" ); document.write( " \"-5%2Ax+%2B+2%2Ay+=+10\"
\n" ); document.write( " \"-5%2Ax+%2B+2%2A-5+=+10\"
\n" ); document.write( " \"-5%2Ax+%2B+-10+=+10\"
\n" ); document.write( " \"-5%2Ax+=+10+-+-10\"
\n" ); document.write( " \"x+=+%2810+-+-10%29%2F-5\"
\n" ); document.write( " \"x+=+20%2F-5\"
\n" ); document.write( " \"x+=+-4\"
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\n" ); document.write( " Therefore, our answer is:
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\n" ); document.write( " \"system%28+x=-4%2C+y=-5+%29\"
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