document.write( "Question 967849: What is the least number that has 4 odd factors that are all the same? Each factor is greater than 1, and can have only 1 and itself as factors. Explain how you find the number. \n" ); document.write( "

Algebra.Com's Answer #591557 by Theo(13342) $\"\"$ $\"About$

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i'm not quite sure what you mean.
\n" ); document.write( "the factors can't be 1.
\n" ); document.write( "the factors have to be odd.
\n" ); document.write( "they have to be the same.
\n" ); document.write( "offhand i would say 3*3*3*3 would be equal to 9*9 = 81.
\n" ); document.write( "the number 81 has 4 odd factors that are all the same.
\n" ); document.write( "can't be 1 because 1 doesn't counts as a factor.
\n" ); document.write( "a prime number has 2 factors.
\n" ); document.write( "1 and itself.
\n" ); document.write( "every number has a factor of 1 and itself.
\n" ); document.write( "what makes a prime number different is that those are the only numbers.
\n" ); document.write( "1 is prime.
\n" ); document.write( "2 is prime because the only factors are 1 and itself.
\n" ); document.write( "3 is prime because the only factors are 1 and itself.
\n" ); document.write( "4 is not prime because the factors are 1 and itself and 2.
\n" ); document.write( "the factors themselves have to be prime is what i think you said.
\n" ); document.write( "3 meets that criteria.
\n" ); document.write( "it's odd.
\n" ); document.write( "it's prime.
\n" ); document.write( "4 of them are factors of 81 because 81 is equal to 3*3*3*3.
\n" ); document.write( "is that what you mean?
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