document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967828>Question 967828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a girls age in 12 years time is the square of her present age. find her present age<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591554 by </B><A HREF=/tutors/aboutme.mpl?userid=Horlaye><B>Horlaye(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Horlaye><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Horlaye><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">      Let the present age be 'p'<BR>\n" );
document.write( "        In twelve years time<BR>\n" );
document.write( "    p + 12 = pē<BR>\n" );
document.write( "    pē - p - 12 = 0<BR>\n" );
document.write( "    pē + 3p - 4p - 12 = 0<BR>\n" );
document.write( "    p(p + 3) -4(p + 3) = 0<BR>\n" );
document.write( "    ( p + 3 ) ( p - 4 ) = 0<BR>\n" );
document.write( "    p + 3 = 0   or   p - 4 = 0<BR>\n" );
document.write( "    p = -3    or   p = 4<BR>\n" );
document.write( "Since one's age cannot be negative <BR>\n" );
document.write( "Therefore her present age is p = 4 </SPAN>\n" );
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