document.write( "Question 967811: The hypotenuse of a right angled triangle exceeds one side by 1cm and the other side by 18cm,Calculate the length of the shortest side? \n" ); document.write( "
Algebra.Com's Answer #591543 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let  x  be the length of the hypotenuse of the given right angled triangle.\r
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\n" ); document.write( "\n" ); document.write( "Then the length of one leg is  x-1,  and the length of the other leg is  x-18,  according to the condition.\r
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\n" ); document.write( "\n" ); document.write( "Then the Pythagorean theorems gives an equation\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2\" + \"%28x-18%29%5E2\" = \"x%5E2\". \r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve it step by step to find  x.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+2x+%2B+1\" + \"x%5E2+-+36x+%2B+324\" = \"x%5E2\",\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+38x+%2B+325\" = \"0\",\r
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\n" ); document.write( "\n" ); document.write( "\"x%5B1%5D\" = \"%2838+%2B+sqrt%2838%5E2+-+4%2A325%29%29%2F2\" = \"%2838+%2B+sqrt%28144%29%29%2F2\" = \"%2838+%2B+12%29%2F2\" = \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x%5B2%5D\" = \"%2838+-+sqrt%2838%5E2+-+4%2A325%29%29%2F2\" = \"%2838+-+sqrt%28144%29%29%2F2\" = \"%2838+-+12%29%2F2\" = \"13\". \r
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\n" ); document.write( "\n" ); document.write( "Thus there are two solutions for the hypotenuse:  25 units and/or  13 units.  Since one leg is 18 units shorter than the hypotenuse,  only one solution has sense:  x = 25.\r
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\n" ); document.write( "\n" ); document.write( "Answer.  The hypotenuse is 25 units long.  The legs are of 24 and 7 units long.  The shortest side is of  7 units long.\r
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